Morley

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Virginia J. Morley, 81 | Obituaries | idahocountyfreepress.com  Idaho County Free Press

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Letha Peacock Obituary (1923 - 2021) - Big Rapids, MI - Big Rapids News  Legacy.com

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Moberly police release photo of weekend robbery suspect - ABC17NEWS  ABC17News.com

Hart baseball opens with losses at Morley-Stanwood tournament  shorelinemedia.net

Ericsson positioned as leader in 5G Frost Radar  Ericsson

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Hello, can someone (in layman terms) describe the results of the Michelson-Morley experiment and how they relate (in terms of overturning physics) to the faster-than-light neutrinos experiment (recently in Time). http://newsfeed.time.com/2012/02/22/einstein-was-right-all-along-faster-than-light-neutrino-was-product-of-error/

We know that velocity of light is c in absolute frame. In the michelson morley experiment , the velocity of light that travelled along the direction of velocity of earth (v) was taken to be c'=c-v which is velocity with respect to earth's reference frame. while the light ray perpendicular to motion of earth was just taken to be c , whereas it should have been 'root under c^2-v^2 , if we added the vectors properly. why it is then taken to be only c instead ? Once again in detail my point is that we are calculating the velocity of the two perpendicular rays (suppose A & B) wrt EARTH'S REFERENCE FRAME . therefore the velocity of ray (say A) moving along the direction of motion of earth is c'=c-v while going & c'=c v while returning (ofcourse wrt Earth's frame). We got c' by vector addition rule which is VECTOR c= VECTOR c' VECTOR v. since here angle is zero, we finally got c'=c-v & c'=c v for ray along A. Similarly for perpendicular ray B, angle between c' and v is pi/2 , therefore we get velocity along B magnitude, c'= [root under(c^2- v^2)] . so it shouldn't be c as c is velocity in absolute frame and if it is taken c, it would mean that earth is taken as a absolute frame for that direction which is false. Inspite of that, c was taken for light ray travelling along B. It is clear that c' wrt EARTH'S FRAME for light travelling along B will be c'= root under c^2 -v^2 . then why c?? c'=velocity of light as observed on earth ie on earth's frame. v=velocity of earth.

I don't quite understand how the Michelson-Morley experiment worked. I understand that if you measure the speed of light in the same direction as the earth is travelling then it would be going slower from the earth's reference frame; c-v. But I don't understand how this has anything to do with the so called "ether" they were trying to measure. If the speed of light wasn't constant, then according to classical relativity you would measure different speeds of light anyway so I don't understand how measuring different speeds would prove there was an ether? If you measure different speeds of sound in air does this prove air (medium) must exist? *please note, I know the ether does not exist and that the speed of light is constant, I'm just trying to understand it from Michelson and Morely's point of view* **And then also, how could you then use this information to actually measure the speed of the ether**?

Hi guys, im struggling to understand about what is reffered to as 'the ether' when this experiment is being explained. all i know is that its a vector you use, to calculate the the velocities of light while its in this 'ether', which is due to the entire system's relative velocity. so lets say, the experiement was performed on a set of wheels, and was moving west to east, would this mean that the 'ether wind' would be moving east to west? like, the light vector will approach and object quicker if that object is approaching the light source? im so confused ahh